Question

in a rhombus ABCD, prove that AC+BD>2AD
please answer
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Answer 1

Step-by-step explanation:

All sides of a rhombus are equal. That means that AB=BC=CD=DA. Therefore AC+BD can be equal to ABCD. And 2AD can also be equal to ABCD. Therefore AC+BD will be *equal* to 2AD. AC + BD is not greater than 2AD. both are equal