In a rhombus ABCD, prove that. AC²+CD²=4BC²
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In △AOB=∠O=90
∘
AB
2
=OA
2
+OB
2
=(
2
AC
)
2
+(
2
BC
)
2
=
4
AC
2
+
4
BD
2
AB
2
=
4
AC
2
+BD
2
∴4AB
2
=AC
2
+BD
2
.
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