Question

In a Rhombus ABCD, the diagonals AC and BD intersect at O, if

AO =4 cm and DO = 3cm , then find the perimeter of the Rhombus.​

Answer 1

Answer:

20cm

Step-by-step explanation:

i hope it is helpfull

Answer 2

Answer:

20 cm is the perimeter of the rhombus

Explanation:

AO = 4cm

DO = 3cm

Diagonals of a rhombus are perpendicular to each other, So ∆AOD is a right angle triangle

According to Pythagorean theorem:

( AD )² = ( AO )² + ( DO )²

( AD )² = ( 4cm )² + ( 3cm )²

( AD )² = 16cm² + 9cm²

( AD )² = 25cm²

AD = √(25cm²)

AD = 5cm

( AD is a side of the rhombus, and all side of a rhombus are equal, So, AD = AB = BC = CD = 5cm )

Perimeter of a rhombus = 4 × side

Perimeter = 4 × 5cm

Perimeter = 20cm