Question

In a rhombus angle DCA =60 degree then what will be the ratio between diagonal AC and BD?

Answer 1

Answer:

AC/BD=1/√3

Step-by-step explanation:

In the ΔOCD

∠DCO=60° and ∠COD=90°

so tan 60=OD/OC

√3 =OD/OC=2OD/2OC=BD/AC( AS O is the bisector of diagonals)

So AC/BD=1/√3

Answer 2

Answer:

AB / BD = 1 /√3

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