In a rhombus,if diagonals are 30 cm and 40 cm ,find its perimeter.
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Answered by
26
Perimeter of a rhombus = 4a
a = [(1/2 d1)^2 + (1/2 d2)^2]^1/2
= [400 + 225]^1/2
= 25
Perimeter = 4 *25 = 100m
a = [(1/2 d1)^2 + (1/2 d2)^2]^1/2
= [400 + 225]^1/2
= 25
Perimeter = 4 *25 = 100m
Answered by
3
The length of one side is 25, therefore, the perimeter of the rhombus will be 100 (all sides of a rhombus are equal)
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