Question

In a Rhombus, length of the one diagonal is 6 cm, another diagonal is thrice the other.
Then its area is​

Answer 1

Answer:

It is 54 cm²

Step-by-step explanation:

length of one diagonal is 6 cm

length of second diagonal=thrice of the other=18 cm

area 1/2x d1 x d2

=54cm²

Answer 2

Let one of the diagonals of rhombus be ‘d_1’ cm and the other be d_2 cm.

Give d_1 = 3 x d_2  

Also d_1 + d_2 = 24 cm  

⇒ d_2 + d_2 = 24  

4d_2 = 24  

d_2 = 244

d_2 = 6 cm  

d_1 = 3 x d2 = 3 x 6  

d_1 = 18 cm  

∴ Area of the rhombus = 12 x d_1 x d_2 sq. units  

= 12 x 18 x 6 cm2 = 54 cm^2  

Area of the rhombus = 54 cm^2