Question

In a Rhombus, length of the one diagonal is 6 cm, another diagonal is thrice the other.
Then its area iispls answer​

Answer 1

Step-by-step explanation:

area = 1(6)(18)/2

=54 sq.cm

formula used is =d1d2/2

please mark as brainlist answer

Answer 2

Given :-

In a rhombus ,

Length of one diagonal is 6cm

Another diagonal length is thrice of other

To find :-

• Area of rhombus

Solution :-

${Area\:of\:Rhombus} = \dfrac{1}{2} d_1 \times d_2$

$\bigstar \underline{ \mathfrak{{According\: to\: Question}}}$

${Length\:of\: diagonal (d_1) = 6cm}$

Length of another diagonal is 3times of other

= 3(6) cm

= 18cm

${Length\:of\:diagonal(d_2) = 18cm}$

Now ,

${Area\:of\:Rhombus} = \dfrac{1}{2} d_1 \times d_2$

$= \dfrac{1}{2} \times 6 \times 18$

$= 3 \times 18$

$= 54cm {}^{2}$

So, area of rhombus is 54cm²

Know more :-

• Area of square - a²
• Area of rectangle = l× b
• Area of triangle = 1/2bh
• Perimeter of square - 4a
• Perimeter of rectangle = 2(l+b)
• Perimeter of equilateral triangle = 3a
• Perimeter of scalene triangle = a+b+c

Here ,

• a denotes side
• b , h denotes base , height
• l , b denotes length , breadth