in a rhombus of side 10 centimetre one of the diagonal is 12 cm long find the length of the second diagonal
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Step-by-step explanation:
consider ∆ABC
(BC)^2= (AB)^2-(AC)^2
=x^2=100-36
= x^2=64
=x=√64
=x=8 cm
total length of diagonal
= x+x
=2x
= 2*8=16cm Answer {x=8}
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