in a rhombus of side 10 cm, one of the diagonal is 12 cm long. find the length of the second diagonal.
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2ond Diagonal = 16 cm
Step-by-step explanation:
Let,
ABCD be a rhombus with side 12 cm
O be the point of intersection of the two diagonals
d¹ = 12 cm
d² = ???
As, diagonals of a rhombus bisect each other, so d¹ = 6+6
Now,
Using Pythagoras Theorem in any of the four triangles so formed,
h² = b²+p²
10² = 6²+p²
100 = 36+p²
100-36 = p²
64 = p²
√64 = p
8 cm = p
Here, we had found the half of the second diagonal
So,
Length of second diagonal = 2×p = 2×8 = 16 cm
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