in a rhombus of side 10 cm one of the diagonal is 12cmlong find the length of the second diagonal
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16 cm
Step-by-step explanation:
we know the Pythagoras theorom
(H)^2 =(0)^2 +(A)^2
10^2 = (6)^2 + (A)^2
100 - 36 = A^2
A^2 = 64
A = √64
A = 8
Therefore,
The diagonal = 8+8
= 16 cm
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