In a rhombus of side 10 cm, one of the diagonals is 12 cm long. Find the length of second diagonal.
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Step-by-step explanation:
In △ABO , applying Pythagoras
AB2=AO2+OB2
102=62+OB2
100−36=OB2
OB=8
BD=2OB
=2×8
=16cm
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