in a rhombus of side 10cm one of the diagonals is 12 cm long find the length of the second diagonal
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Answer =16 cm
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let half length of one diagonal be x
since diagonal bisect each other so half length of given diagonal=12/2
=6cm
take any triangle in the rhombus
since diagonals of rhombus bisect each other at 90°
using Pythagoras thereom
10²=6²+x²
x²=100-36
x²=64
x=8
so length of other diagonal is 2×x
2×8
16 cm
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