In a Rhombus, one diagonal is four times of the other diagonal. If the area of Rhombus is 968 cm2, then find the diagonals.
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Let the diagonals of the rhombus be a and b
then, b−a=4 or b=(4+a)
Area of rhombus =
2
1
ab=30
a(4+a)=60
4a+a
2
=60
a
2
+4a−60=0
a=
2
−4±
16+240
=
2
−4±16
∴a=6,−10
Taking only positive value of a
Other diagonal =6+4=10cm
Thus diagonals are 6cm and 10cm
Step-by-step explanation:
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