in a rhombus one diagonal is four times the other. if the area of rhombus is 968 sq m then find the diagonal
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4
Answer:
38 m is the diagonal...
Answered by
2
Step-by-step explanation:
Area of rhombus =(diagonal 1*digonal2)/2
as given in the question;
d1 =4 times of d2
i,e; d1=4d1
put in formula:-
968 = (4d1×d1) /2
968 = 2d1²
d1² = 968/2
d1² = 484
d1 = √484
d1 = 22
so ;
d2 = 4d1
d2 = 4×22
d2 = 88
Thanks
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