Question

In a rhombus PQ, PR and QS are diagonals. If PR= 24cm and QS=18cm, find the length of the side of the rhombus​

Answer 1

Answer:

Let the point of intersection of the diagonals of the rhombus be denoted by the point O

PO = PR / 2 = 12cm

QO = QS / 2 = 9cm

PQ = $\sqrt{PO^{2} + OQ^{2} } = \sqrt{12^{2} + 9^{2} }$

​

      =$\sqrt{144 + 81} = \sqrt{225}$

      = 15 cm

Therefore, side = 15 cm.