Question

In a rhombus PQRS, diagonal PR and Qs meet each other at O. If PRQ = 50°, find psq

with explanation​

Answer 1

Answer:

40°

Step-by-step explanation:

Diagonal of rhombus bisect each other at 90°.

90°+50°+angle psq = 180°

angle psq = 40°

Answer 2

180-140

in rohmbus opposite sides are equal and parallel

angle PRQ =50°

Now,

PS parallel to QR

therefore an angle SPR= angle PRQ=50°

Now in ∆POS

angle SPO+anglePOS+angle PSO=180°

50°+90°+angle PSO=180°

[reason--

angle SPO =angle SPR

diagonals of rohmbus are perpendicular to each other.]

angle PSO=40°

But angle PSO==angle PSQ

therefore, angle PSQ=40°

It may be useful!