Question

In a rhombus PQRS, PQ=10cm, PR=16cm, length of diagonal SQ=?​

Answer 1

Answer:

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Step-by-step explanation:

Side of Rhombus are equal.

AB = BC = CD = DA

∴AC= 4×(side) 2−(DiagonalBD) 2

AC= 4×(10) 2−(16) 2

= 400−256

= 144

=12cm