Math, asked by Coco324, 1 year ago

in a rhombus PQRS, PQ=4 cm, then the sum of the squares of the diagonals a)32cm b)64cm c)16cm d)8cm

Answers

Answered by nova5

Hey mate thank for the question
Hope it helps
Side of rhombus=4cm
Since diagnols of rhombus are equal
so AC=4cm
BD=4cm
ATP=>
There are to diagnols so their sum
=(4)^2+(4)^2
=16+16
=32

udayalchau0000: Yeah

udayalchau0000: it’s 32

Coco324: cuz according to my text book and GOOGLE they are not!!!

udayalchau0000: Ok sorry bro you are right but by Pythagoras theorem you can get the answer

Coco324: for crying out loud I have been trying it since a long time but I couldn't figure it out!! ... that's why post the question

udayalchau0000: Ohh so you can search it on some other website

Coco324: dude you try to google it ... you won't find any answers or any question resembling to it

nova5: plzz mark as brainliest

Coco324: why should I if the ANSWER IS WRONG!!!!!!

Coco324: unless I find the right answer with detailed explanation I will not mark any answer brainliest

Answered by udayalchau0000

Ithe answer in (a) part 32cm

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