In a rhombus PQRS, PQ=5cm then PQ square +QS square is
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0
Answer:
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Step-by-step explanation:
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Answered by
3
Step-by-step explanation:
in rhombus PQRS, we know that PQ=QR=SR=PS
Now by pythagoras theorem
PQ^2+PS^2=QS^2
5^2+5^2=QS^2
25+25=QS^2
QS^2=50
Now PQ^2+QS^2=25+50
=75
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