Question

In a rhombus the diagonals are 12cm and 16cm. Find the perimeter of rhombus

Answer 1

Step-by-step explanation:

$2 \sqrt{p { }^{2} + q {}^{2} }$

$2 \sqrt{16 { }^{2} + 12 {}^{2} }$

$4 \sqrt{10}$

Answer 2

Question:-

The lengths of the diagonals of a rhombus are 16cm and 12cm. then find the length of the side of rhombus

Solution:-

we know that diagonal of rhombus,bisect each other in right angle ( 90° ).

we also know that all sides of rhombus are equal ( of equal length ).

so, now

Let rhombus is ABCD and

Diagonal of rhombus are

BD = 16 cm and AC = 12 cm

means,

OD = 8 cm and AO = 6 cm

By pythagorus theorem

To find length of AD ( and all side of rhombus )

=> (AD)² = (OD)² + (AO)²

=> (AD)² = (8)² + (6)²

=> (AD)² = 64 + 36

=> (AD)² = 100

=> AD = √100

=> AD = 10 cm

=>Perimeter of rhombus = 4 × ( side )

=>Perimeter of rhombus = 4 × 10

=>Perimeter of rhombus = 40 cm

Hence length of all side of rhombus

is 10 cm and perimeter of rhombus is 40 cm.

i hope it helps you.