Question

In a rhombus, the diagonals are in the ratio 4:5 . If it's area is 490 cm² , length of the smaller diagonal is

Answer 1

Answer:

28 cm

Step-by-step explanation:

let the length be x cm

therefore 4&5 = 4x and 5x

because area of rhombus=

$\frac{1}{2} \times diagonal \: \times diagonal$

$= \frac{1}{2} \times 4x \times 5x = 490 \\ 10 {x}^{2} = 490 \\ {x}^{2} = 49 \\ x = \sqrt{49 } = 7$

therefore length of smaller diagonal=4x= 28 cm