Question

In a rhombus there is one diagonal and other is four times greater the other diagonal the area is 968 cm²,then find the diagonals measurements

Pls give step by step explanation I will mark as BRAINLIEST ANSWER AND THANK​

Answer 1

Answer:

The Diagonals Are 22cm and 88cm

Step-by-step explanation:

Let The Diagonals Be x and 4x

Diagonal 1 (d1) = x

Diagonal 2 (d2) = 4x

Area = 968 m²

$area \: of \: rhombus = \frac{1}{2} \times d1 \times d2 \\ = ) \frac{1}{2} \times x \times 4x = 968 \\ = )x \times 2x = 968 \\ = )2 {x}^{2} = 968 \\ = ) {x}^{2} = \frac{968}{2} \\ = ) {x}^{2} = 484 \\ = )x = \sqrt{484} \\ = )x = 22$

Therefore The Diagonal are :-

a) d1 =) x = 22

d2 =)4x = 22 x 4

=)88

Hope it helped