Question

In a rhombuz, if diagonal are 30 cm and 40 cm, find its perimeter.​

Answer 1

Step-by-step explanation:

area= 1/2 × 30 × 40

= 15× 40

= 600 cm square

Answer 2

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In a rhombus, if diagonal are 30 cm and 40 cm, find its perimeter.

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Diagonal of a Rhombus are :30 cm and 40 cm

We have to find sides of a rhombus then we are able to find its perimeter.

Perimeter of a Rhombus=4×Side

Diagonal AC & BD ARE 30 CM & 40 CM Respectively.

AO=AC/2=30/2=15cm

BO=BD/2=40/2=20cm

By Pythagoras theorem:

${(AB)}^{2} = {(AO)}^{2} + {(BO)}^{2}$

$= > {(AB)}^{2} = {(15)}^{2} + {(20)}^{2}$

$= > {(AB)}^{2} = 225 + 400 = 625$

$= > {(AB)}^{2} = 625$

$= > AB= \sqrt{625} = 25$

Know :All sides of a rhombus are equal in length.

So,sides of a Rhombus are 25 cm ,25cm ,25 cm &25 cm

Perimeter of a Rhombus =4×Side

Perimeter of a Rhombus =4×Side=>4×25=100cm

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