Math, asked by deepanshubhati30sept, 4 months ago

In a right ∆ ABC , right angled at B , if sin A=3/5, find all the six trigonometric ratios of angle C

Answers

Answered by danielinjeti700
1

Step-by-step explanation:

HeRe Is Your Ans ⤵

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{ H² = P² + B²

B² = 5² - 3²

B = 4 }

➡Sin A = P / H = 3 / 5

➡Cos A = B / H = 4 / 5

➡Tan A = P / B = 3 / 4

➡Cot A = B / P = 4 / 3

➡Sec A = H / B = 5 / 4

➡Cosec A = H / P = 5 / 3

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