In a right ∆ ABC , right angled at B , if sin A=3/5, find all the six trigonometric ratios of angle C
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Step-by-step explanation:
HeRe Is Your Ans ⤵
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{ H² = P² + B²
B² = 5² - 3²
B = 4 }
➡Sin A = P / H = 3 / 5
➡Cos A = B / H = 4 / 5
➡Tan A = P / B = 3 / 4
➡Cot A = B / P = 4 / 3
➡Sec A = H / B = 5 / 4
➡Cosec A = H / P = 5 / 3
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