Question

In a right ∆ABC, right angled at B, if tanA =1 then find 2sinAcosA​

Answer 1

Answer:

Apply the formula and then do it

Answer 2

Step-by-step explanation:

In right ∆ABC

GIVEN THAT :-

TanA = 1

TanA = Tan45°

so

A =45° ✓✓

TO FIND :-

The value of

2SinACosA = Sin2A = Sin2×45°

= Sin 90° = 1

CONCLUSION:-

Answer is 1