In a right angle traingle abc rigjt angle is at
b.ab+bc =23cm and ab-bc= 7 cm then find sin a
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ab+bc=23
ab-bc=7
________
+. -. +
2ab=30
ab=30/2
ab=15
bc=8
by pytagorous theorem,
(ab)^2+(bc)^2=(ac)^2
(15)^2+(8)^2=(ac)^2
125+64=(ac)^2
289=(ac)^2
√289=ac
ac=17
sinA=bc/ac
= 8/17
ab-bc=7
________
+. -. +
2ab=30
ab=30/2
ab=15
bc=8
by pytagorous theorem,
(ab)^2+(bc)^2=(ac)^2
(15)^2+(8)^2=(ac)^2
125+64=(ac)^2
289=(ac)^2
√289=ac
ac=17
sinA=bc/ac
= 8/17
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