In a right angle traingle side ac =18,bc=10find ab
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let a triangle ABC in which AC is the hypotenuse AB is perpendicular and BC is the Base.
AC^2=AB^2+BC^2
AB^2=AC^2-BC^2
AB^2=(18)^2-(10)^2
AB =root under 324-100
= root 224
14.96
AC^2=AB^2+BC^2
AB^2=AC^2-BC^2
AB^2=(18)^2-(10)^2
AB =root under 324-100
= root 224
14.96
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