in a right angle triangle ab=5cm, bc=5cm find ac /hypotenuse
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Answered by
2
In a right triangle ABC,
AB = 5 cm
BC = 5 cm
So, AC² = 5²+5² = 25+25 = 50
=> AC = √50 = 5√2 cm
Therefore, the length of the hypotenuse AC is 5√2 cm.
AB = 5 cm
BC = 5 cm
So, AC² = 5²+5² = 25+25 = 50
=> AC = √50 = 5√2 cm
Therefore, the length of the hypotenuse AC is 5√2 cm.
Answered by
1
As we know to find any side of a right triangle we will use Pythagoras theorem
ac² = ab²+ bc²
= 25+ 25
= √ 50
= 7.07
ac² = ab²+ bc²
= 25+ 25
= √ 50
= 7.07
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