in a right angle triangle abc, ab= ac then a: b: c is
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Answered by
2
Answer:
Step-by-step explanation:
let AC = x
then BC = 2–√x
as AD and DB will be in ratio of AC and BC by angle bisector theorem
so let AD = y and so DB = 2–√y
but AD + DB = AB = AC
so y+2–√y = x
y(2–√ + 1) = x
so y = x2–√+1
on rationalising the denominator it results in
y = (2–√ - 1) x
add x on both sides
y + x= (2–√ - 1) x + x
AD + AC = (2–√ - 1 + 1) x
AD + AC = (2–√) x
so AC + AD = BC
Answered by
3
Since, ab=ac
Therefore angle a = angle c = 45 degree
Angle b = 90
a:b:c = 45:90:45 = 1:2:1
Therefore angle a = angle c = 45 degree
Angle b = 90
a:b:c = 45:90:45 = 1:2:1
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