Math, asked by meghanamadala143, 2 months ago

In a right angle triangle ABC AB=X cm,BC=(x+5),AC=25 cm then x=

Answers

Answered by anchal12jain
0

Answer:

x = 15

Step-by-step explanation:

AB² + BC² = CA²

x² + (x + 5)² = 25²

x² + x² + 10x + 25 = 625

2x² + 10x - 600 = 0

2x² + 40x - 30x - 600 = 0

2x(x + 20) - 30(x + 20) = 0

(2x - 30)(x + 20) = 0

(2x - 30) = 0 or (x + 20) = 0

2x = 30 or x = -20

x = 15 or x = -20

since length cannot be negative, x = 15

Answered by soumyavaishnavivinu
0

Answer:

x=15

Step-by-step explanation:

AB2 +BC2=CA2

x2+(x+5)=25

x2+x2+0x+25=625

2x2+10x-600=0

2x2+40*-36*-600=0

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