Question

In a right angle triangle ABC, angel ABC=90. A circle with radius r is inscribed in triangle ABC, a, b and c are the length of side BC, AC and AB respectively.
Prove that 2r = a+b +c. ​

Answer 1

I have slightly changed the naming of sides

And in the question it should be 2r=a+b-c

Now, AE = AD = (a - r)

& EC = CF = b-r

AC = a -r+ b -r

or c = a + b - 2r

2r = a + b -c

similarly you can solve your question by considering the sides you have taken

Answer 2

Answer:

Mark me as brainliest

Step-by-step explanation:

Answer is in pictures