Question

in a right angle Triangle ABC ,ANGLE B is 90°,if tanc =1 then angle A is
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Answer 1

Answer:

45

Step-by-step explanation:

In △ABC, ∠ABC=90°

∴tanC= AB/BC =1

Since tanC=1 (Given)

AB=BC

∴BC=AB

Let

AB=BC=k, where k is a positive number.

Now,

AC^2 = √AB^2 + BC^2 =√k^2+k^2

AC=k√2

sin A = 1/√2

cos A= 1/√2

hence,

Side of triangles are equal and angle B is 90

AB=BC

therefore

Angle A= Angle C = 45°