Question

In a right angle triangle ABC ∠B= 90° ∠A=45°.side AB = 2 cms. Find side AC=?​

Answer 1

70 is the answer follow plz this answer and me

Answer 2

Answer:

$\sqrt{2}$

Step-by-step explanation:

From Right angled ️ABC,

$\frac{ac}{ab} = \sin(45)$

$\frac{ac}{2} = \frac{1}{ \sqrt{2} }$

$\sqrt{2} \times ac = 2$

$then$

$ac = \frac{2}{ \sqrt{2} } \frac{ \times \sqrt{2} }{ \times \sqrt{2} }$

The root 2 are multiplied in both the nominations to equalize them and simplify it.

$ac = \frac{ \sqrt[2]{2} }{2}$

Hence,

$ac = \sqrt{2}$