in a right angle triangle ABC right amgle at C bc+ca=23cm,and bc-ca =7cmthen find sinA and sinB
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BC+CA=23
BC-CA = 7
Adding these two equations
2BC=30
BC=15
Substituting this value in the first equation
15+CA=23
CA=8
+= (by pythagorus theorem)
⇒(15*15)+(8*8)=
225+64=
=289
⇒AC=17
BC-CA = 7
Adding these two equations
2BC=30
BC=15
Substituting this value in the first equation
15+CA=23
CA=8
+= (by pythagorus theorem)
⇒(15*15)+(8*8)=
225+64=
=289
⇒AC=17
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