Question

In a right angle triangle ABC right angle at C. BC +CA= 23 cm and BC-CA= 7 . Then find sin A and tan B
I will mark as brainlist​

Answer 1

Answer:

BC+CA=23

BC-CA  = 7

Adding these two equations

2BC=30

BC=15

Substituting this value in the first equation

15+CA=23

CA=8

BC^{2}BC2 +AC^{2}AC2 =AB^{2}AB2 (by pythagorus theorem)

⇒(15*15)+(8*8)=AB^{2}AB2

225+64=AB^{2}AB2

AB^{2}AB2 =289

⇒AC=17

Now,

SinA= 15/17

tanB = 8/15

Hope it helps...

Answer 2

Answer:

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