In a right angle triangle ABC , right angle at C . BC+CA=23cm and BC - .CA = 7cm then find tan B and sin A
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by using trigonometric ratio you will get tan B and sin A....
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saksham3616:
tan B = 8/15 and Sin A = 15/7
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BC+CA=23
BC-CA=7
THEN,
BC=7+CA
PUT IN IST EQUATION
7+CA+CA=23
2CA=23-7
2CA=16
CA=8 SO,
BC=7+8=15 NOW WE CAN FIND ANS
AB=√CA^+BC^
AB=√64+225
AB=√289=17
tan B=BC/AC
15/8 AND
SIN A=AC/AB
=8/17 ANS|
BC-CA=7
THEN,
BC=7+CA
PUT IN IST EQUATION
7+CA+CA=23
2CA=23-7
2CA=16
CA=8 SO,
BC=7+8=15 NOW WE CAN FIND ANS
AB=√CA^+BC^
AB=√64+225
AB=√289=17
tan B=BC/AC
15/8 AND
SIN A=AC/AB
=8/17 ANS|
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