In a right angle triangle abc right angle at c if tan a=1 then verify that 2sin a cosa =1
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since tanA=1 A=45° and B=45°
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⇒ Given :- ABC is a right angled triangle at C
tan A = 1
⇒ To verify :- 2 sin A cos A = 1.
⇒ Solution:- In ∆ ABC
tan A = 1
BC/AC = 1
BC = x & AC = x
By Pythagoras theorem
AB^2 = AC^2 + BC^2
AB^2 = x^2 + x^2
AB = √2x
sin A = BC/AB
= x/√2x
= 1/√2x
cos A = AC/AB
= x/√2x
= 1/√2x
2 sin A cos A =
2 × 1/√2 × 1/√2
= 1
Hence verified!
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