In a right angle triangle ABC, right
angle is at B, if tan A = root 3, then find
the value of
i) sin A cos C + cos A sin C
ii) cos A cos C-sin A sin C (AS)
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tan A= root 3
A=60
B= 90
So, C= 30
sinAcosC+cosAsinC=sin(A+C)
sin (60+30)
sin(90) = 1
the Answer is 1
plz, mark it as brainlist answer
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