In a right angle triangle ABC, right angle is at B, if tan A= root3 then find the value of
(i) sin A cos C+ cos A sin C
(ii) cos A cos C-sin A sin C
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0
Answer:
1)5/4 2) 0
Step-by-step explanation:
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Answer:
(i) 1
(ii) 0
Step-By-Step Explanation:
(i) sin A cos C+ cos A sin C
Given: tan A = √3
⇒ Tanθ = Opposite/Adjacent = BC/AB =
Let: BC = √3k, AB = 1k
∴ By Pythagoras Theorem,
= (AC)² = (AB)² + (BC)²
= (AC)² = (1k)² + (√3k)²
= (AC)² = 1k² + 3k²
= AC² = 4k²
= AC = √4k² (√,² gets Cancelled)
= AC = 2k
∴
=
(ii) cos A cos C-sin A sin C
= x - x (All [k's] will get Cancelled)
= = 0
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