Question

In a right angle triangle ABC, right angle is at B, if tan A= 13 then find the value of
(i) sin A cos C + cos A sin C
(ii) cos A cos C-sin A sin C write the solution ​

Answer 1

Explanation:

tanA=√3

A=60°

B=90°

C=180-(A+B)=180-150

C=30°

sinAcosC+cosAsinC

sin(A+C)

sin(60+30)

sin90

1

cosAcosC-sinAsinC

cos(A+C)

cos(60+30)

cos90°

0