Question

In a right angle triangle ABC,right angle is at B,if tan A =√3 then find the value of

1.sin A cos C + cos A sin C​

Answer 1

Answer:

sinAcosC+cosAsinC= 1

Step-by-step explanation:

In △ABC,

∠B=90°, tanA=1/3=AB/BC

Let BC =1x & AB= 3x

AC²=AB²+BC²

AC²= (√3x)² + (x)²

AC²= 4x²

AC= 2x

sinAcosC+cosAsinC= 1/2 × 1/2 + √3/2 × √3/2

= 1/4+3/4

= 1