Question

In a right angle triangle ABC, right angle is at B, if tan A= 13 then find the value of
(i) sin A cos C + cos A sin C
(ii) cos A cos C-sin A sin C​

Answer 1

Answer:

Step-by-step explanation:

SinA=BC/AC and CosC=BC/AC

Therefore,SinA . CosC=BC^2/AC^2

CosA=AB/AC and SinC=AB/AC

Therefore,CosA . SinC= AB^2/AC^2

SO, SinsA . CosC + CosA . Sin C= BC^2+AB^2/AC^2= AC^2/AC^2=1