Question

In a right angle triangle ABC, right angle is at C. BC + CA = 23 cm and
BC-CA= 7cm, then find sin A and tan B.​

Answer 1

Answer:

Sin A = 15/17

Tan A = 8/15

Step-by-step explanation:

Given

BC+CA =23

BC-CA = 7

Proof

BC= 7+CA

Putting the value in BC+CA =23

7+CA+CA = 23

2CA=23-7

2CA =16

CA = 16/2

CA = 8

BC= 7+8

= 15

(H)^2 = (P)^2 + (B)^2

" = (8)^2 + (15)^2

" = 64+225

" = 289

H = 17

Sin A = BC/AB = 15/17

Tan B = AC/BC. = 8/15