Question

in a right angle triangle ABC, right angle is at C. BC + CA = 23 cm
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BC-CA= 7cm. then find sin A and tan B.​

Answer 1

Answer:

According to question

BC+CA=23. (1)

BC-CA=7. (2)

(-). (+). (-)

2CA=16

CA=16/2

CA=8cm

Substituting CA=8 in (1)

BC+8=23

BC=23-8

BC=15cm

According to Pythagoras theorem

CA^2+BC^2=AB^2

8^2+15^2=AB^2

AB^2=64+225

AB^2=289

AB=√289

AB=17cm

Sin A=P/H

15/17

Tan B=P/B

8/15

See the figure