Question

in a right angle triangle
ABC right angle is at C. BC+CA=23cm and BC-CA =7cm then find sinA and tanB

Answer 1

in a right angle triangle ABC right angle is at C.
by Pythagoras theorem
${(ab)}^{2} = {(ac)}^{2} + {(bc)}^{2}$
BC+CA=23cm and BC-CA =7cm
by adding both equation
2BC=30
BC=15cm

and CA=8cm

by Pythagoras triplet
AB=17cm

sinA=BC/AB=15/17
tan B=AC/BC=8/15