Question

in a right angle triangle ABC,right angle is at C.BC+CA=23cm andvBC-CA=7cm,then find sinA and tanB

Answer 1

BC+CA=23
BC-CA  = 7
Adding these two equations
2BC=30
BC=15
Substituting this value in the first equation
15+CA=23
CA=8
+= (by pythagorus theorem)
⇒(15*15)+(8*8)=
225+64=
=289
⇒AC=17

So, sinA=opposite side/hypotenuse=CB/AB=15/17 tanB=opposite side/adjacent side=AC/CB=8/15 

Hope This Helps :)