Question

In a right angle triangle ABC, right angle is at C. BC+CA=23cm and BC-CA=7cm, then find sinA + sinB

Answer 1

Answer:

GIVEN

BC+CA=23

BC-CA=7

2BC=30

BC=15

SUBSTITUTING IN ANY OF THE ONE EQ.

BC+CA=23

15+CA=23

CA=8

AB=17

sinA=15/8

sinB=8/17

sinA+sinB=15/8+8/17

255+64/136

319/136 May be the answer