Question

In a right angle triangle ABC, right angled at C in which AB= 13 cm ,BC= 5 cm determine the value of cos²B+Sin ²A​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge\bf\red{Question}$

In a right angle triangle ABC, right angled at C in which AB= 13 cm ,BC= 5 cm determine the value of cos²B+Sin ²A

$\huge\bf\pink{Solution}$

We have,

• CosB = BC/AB = 5/13
• SinA = BC/AB = 5/13

➡ Cos²B + Sin²A = 25/169 + 25/169

➡ 25 + 25/169

➡ 50/169