Question

in a right angle triangle ABC right angled at c, p and q are points of side CA and CB respectively which divide the sides in the ratio 2 is to 1 prove that 9aq square =4 BC square + 9AC square

Answer 1

In a right angle triangle ABC right angled at c, p and q are points of side CA and CB respectively which divide the sides in the ratio 2 is to 1