Question

In a right angle triangle ABC where AB= 5cm BC= 12cm and the angle between ABC =90° then find its trigonometric ratio

Answer 1

$\large \mathbb{ \red{ \underline{SOLUTION}}}$

ABC is right angled trangle with angle ABC = 90°

So, AC = $[√{(5^2) + (12^2)}]$ cm = 13 cm.

We know, for any angled traingle, the circumcenter coincides with the midpoint of the hypotenuse.

So, length of radius the circumcircle = $\sf \frac{13}{2} \: cm = 6.5 \: cm.$

Answer 2

ABC is right angled trangle with angle ABC = 90°

So, AC = $[√{(5^2) + (12^2)}]$ cm = 13 cm.

We know, for any angled traingle, the circumcenter coincides with the midpoint of the hypotenuse.

So, length of radius the circumcircle = $\sf \frac{13}{2} \: cm = 6.5 \: cm</p><p>$